(2x^2-7x+1)(4x+3)=

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Solution for (2x^2-7x+1)(4x+3)= equation: 


Simplifying
(2x2 + -7x + 1)(4x + 3) = 0

Reorder the terms:
(1 + -7x + 2x2)(4x + 3) = 0

Reorder the terms:
(1 + -7x + 2x2)(3 + 4x) = 0

Multiply (1 + -7x + 2x2) * (3 + 4x)
(1(3 + 4x) + -7x * (3 + 4x) + 2x2 * (3 + 4x)) = 0
((3 * 1 + 4x * 1) + -7x * (3 + 4x) + 2x2 * (3 + 4x)) = 0
((3 + 4x) + -7x * (3 + 4x) + 2x2 * (3 + 4x)) = 0
(3 + 4x + (3 * -7x + 4x * -7x) + 2x2 * (3 + 4x)) = 0
(3 + 4x + (-21x + -28x2) + 2x2 * (3 + 4x)) = 0
(3 + 4x + -21x + -28x2 + (3 * 2x2 + 4x * 2x2)) = 0
(3 + 4x + -21x + -28x2 + (6x2 + 8x3)) = 0

Combine like terms: 4x + -21x = -17x
(3 + -17x + -28x2 + 6x2 + 8x3) = 0

Combine like terms: -28x2 + 6x2 = -22x2
(3 + -17x + -22x2 + 8x3) = 0

Solving
3 + -17x + -22x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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